When a large star has spent all its nuclear energy it finally contracts due to its own gravity and becomes?

When a large star has spent all its nuclear energy it finally contracts due to its own gravity and becomes a dense small object called a neutron star. Many such stars are found to be rotating with a high speed. How can you account for this high rate of rotation particularly when most stars like our sun are rotating very slowly?When a large star has spent all its nuclear energy it finally contracts due to its own gravity and becomes?I believe many scientists believe this is due to a black hole in the vacinity of the star.When a large star has spent all its nuclear energy it finally contracts due to its own gravity and becomes?
Conservation of angular momentum and asymmetric ejection of mass during the nova (or supernova) stages.When a large star has spent all its nuclear energy it finally contracts due to its own gravity and becomes?It depends upon the original mass of the star. The more massive, the bigger the blast that blows away the star's outer layers, and the bigger the blast, the faster the remnant will spin.When a large star has spent all its nuclear energy it finally contracts due to its own gravity and becomes?
Neutron stars spin faster than their parent stars because angular momentum is conserved in the collapse, but the angular inertia of the tiny neutron star is vastly smaller than the parent star.聽 The same angular momentum with less angular inertia works out to higher rotational speed.When a large star has spent all its nuclear energy it finally contracts due to its own gravity and becomes?As the stellar core shrinks,it must rotate faster in order to conserve its angular momentum.