Star A is a main sequence star with a surface temperature of 4000 degrees K. Star B is a red giant with the same surface temperature as Star A, but Star B is measured to be 6 times more luminous than Star A. How many times larger in diameter is Star B than Star A?How much larger is the diameter of one star?Luminosity L is proportional to R^2 T^4. So we can write:
L_B/L_A = (R_B/R_A)^2 (T_B/T_A)^4 =%26gt;
6 = (R_B/R_A)^2 =%26gt;
R_B = 2.45 R_A
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