How do I find time it takes to get to the star?

People hoping to travel to other worlds are faced with huge challenges. One of the biggest is the time required for a journey. The nearest star is 4.1*10^16 m away. Suppose you had a spacecraft that could accelerate at 1.5 g for one third of a year, then continue at a constant speed.



Can anyone help me before Wednesday?How do I find time it takes to get to the star?Do you know what relativity is? Is this a relativistic question? The answer is far different than if it is. I'll assume that you don't know and that m is meters.



1/3 of a year is 366/3 days (This is a leap year). 1/3 year = 122 days.



122 days = 24 * 3600 seconds. (the units of g are in meters per second squared.)

acceleration time = 10540800 seconds.



t = 1054800 seconds

1.5 g = 1.5 * 9.81 = 14.715 m/s^2

a = g1 = 14.715 m/s^2

vi = 0 m/s



You need both vf and d for the acceleration period.



a = (vf - vi)/t

14.715 = vf/1054800

vf = 15521382



d = (vi + vf)*t/2

d = (0 + 15521382)*1054800/2 which is pretty big.

d = 8.19*10^12 meters.



The remaining distance is absolutely huge, almost the same as the given number.



d_remaining = 4.1*10^16 - 8.19*10^12

d_remaining = 4.0992 * 10^16



time = d_remaining / vf

vf = 15521382 m/s

t = ???????????????????



t = 4.0992*10^16/15521382 = 2.64*10^9 seconds.

t = 2.64*10^9 seconds*[hr/3600s]*[1day/24 hr]*[1 year/365 days ]

t = 83.71 years



This is numerically correct: I'd check the decimal point though. My calculator has the blues today.