What happens when the gravity of a massive star is able to overcome neutron degeneracy pressure?

a. The core contracts and becomes a white dwarf.

b. The core contracts and becomes a ball of neutrons.

c. The core contracts and becomes a black hole.

d. The star explodes violently, leaving nothing behind.

e. Gravity is not able to overcome neutron degeneracy pressure.What happens when the gravity of a massive star is able to overcome neutron degeneracy pressure?The maximum mass of a neutron star is given by: -



........................ 鲁/鈧?br>
M(max) = |8蟺f(n)| . 1.85.M(sun)

.............. |_____|

.............. | .. 9 . |



Where f(n) is a dimensionless length parameter (for ordinary nuclear matter f(n) 鈮?0.9).



Thus, in neutron stars of 3.0.M(sun) - 5.0.M(sun) the gravity of the massive star is able to overcome neutron degeneracy pressure at the core. The star collapses and gravity strengthens and the star enters a region of space-time called a black hole.



Thus, the answer to your question is ---- c.What happens when the gravity of a massive star is able to overcome neutron degeneracy pressure?http://answers.yahoo.com/question/index?鈥?/a>