How do I find the energy of each square meter on the surface of a star?

I need to figure out how much more energy a 30,000 K star puts out than a 6,000 K star. Does anyone have a formula?How do I find the energy of each square meter on the surface of a star?Stefan-Boltzmann radiation law.



L = (7.1256E-7 W m^-2 K^-4) R^2 T^4



where R is the star's radius

where T is the star's effective temperature

where L is the star's luminosity



F = L / (4 pi R^2)



Where F is the power flux per square meter of the star's surface.



F = (5.6704E-8 W m^-2 K^-4) T^4



So a star having a 30000 Kelvin effective temperature radiates 625 times more power from each square meter of surface than a 6000 Kelvin star does.How do I find the energy of each square meter on the surface of a star?Thanks! I wish that the work I put into answering questions always paid off, but sometimes it doesn't. Have a look at this one:

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How do I find the energy of each square meter on the surface of a star?There should be one, the short answer is 5 times. Although the real answer could be much higher.How do I find the energy of each square meter on the surface of a star?
The radiation per square meter from a black body (which a star isn't, but it is a workable approximation) goes as the fourth power of the temperature. Since in this case the ratio is 5, the hotter star puts out an astounding 625 times as much energy per square meter as the cooler one. This is called Stefan's law.