A newly discovered planet orbits a distant star with the same mass as the Sun at an average distance of 116 million kilometers. Its orbital eccentricity is 0.4. I tried using keplers third law the equation P^2*au^3 and solving for P but the answer came out very funny, please help.A newly discovered planet orbits a distant star with the same mass as the Sun at an average distance of 116 mi?It's not clear what your question is. Keppler's is a good choice if you're being asked to find the period of the planet.
(T虏 / D鲁)sys1 = (T虏 / D鲁)sys2
sys1:
T = 1yr
D = 150e6 km = 1.5e11 m
sys2:
T = ?
D = 116e6 km = 1.16e11 m
(1yr)虏 / (1.5e11m)鲁 = T虏 / (1.16e11m)鲁
T = 0.68 yr
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